Search a number
-
+
2100454153 = 7436978253
BaseRepresentation
bin111110100110010…
…0110001100001001
312102101101010102021
41331030212030021
513300204013103
6544232004441
7103023365020
oct17514461411
95371333367
102100454153
11988719326
124a7530721
132762197a5
1415cd678b7
15c4606bbd
hex7d326309

2100454153 has 8 divisors (see below), whose sum is σ = 2456345408. Its totient is φ = 1758519504.

The previous prime is 2100454151. The next prime is 2100454157. The reversal of 2100454153 is 3514540012.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2100454153 - 21 = 2100454151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2100454151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3488826 + ... + 3489427.

It is an arithmetic number, because the mean of its divisors is an integer number (307043176).

Almost surely, 22100454153 is an apocalyptic number.

It is an amenable number.

2100454153 is a deficient number, since it is larger than the sum of its proper divisors (355891255).

2100454153 is an equidigital number, since it uses as much as digits as its factorization.

2100454153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6978303.

The product of its (nonzero) digits is 2400, while the sum is 25.

The square root of 2100454153 is about 45830.7118971547. The cubic root of 2100454153 is about 1280.6714724398.

Adding to 2100454153 its reverse (3514540012), we get a palindrome (5614994165).

It can be divided in two parts, 21004 and 54153, that added together give a palindrome (75157).

The spelling of 2100454153 in words is "two billion, one hundred million, four hundred fifty-four thousand, one hundred fifty-three".

Divisors: 1 7 43 301 6978253 48847771 300064879 2100454153