Base | Representation |
---|---|
bin | 11110100100011100001… |
… | …001100011110110110001 |
3 | 21102211022011212202101121 |
4 | 132210130021203312301 |
5 | 233404224041312303 |
6 | 4245015313102241 |
7 | 304525404140263 |
oct | 36443411436661 |
9 | 7384264782347 |
10 | 2100711275953 |
11 | 73a9a7828054 |
12 | 29b16bb57981 |
13 | 123133530754 |
14 | 73964181b33 |
15 | 3999e8b59bd |
hex | 1e91c263db1 |
2100711275953 has 2 divisors, whose sum is σ = 2100711275954. Its totient is φ = 2100711275952.
The previous prime is 2100711275899. The next prime is 2100711275977. The reversal of 2100711275953 is 3595721170012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1286371077489 + 814340198464 = 1134183^2 + 902408^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100711275953 - 225 = 2100677721521 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100711275153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050355637976 + 1050355637977.
It is an arithmetic number, because the mean of its divisors is an integer number (1050355637977).
Almost surely, 22100711275953 is an apocalyptic number.
It is an amenable number.
2100711275953 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100711275953 is an equidigital number, since it uses as much as digits as its factorization.
2100711275953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 132300, while the sum is 43.
The spelling of 2100711275953 in words is "two trillion, one hundred billion, seven hundred eleven million, two hundred seventy-five thousand, nine hundred fifty-three".
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