Base | Representation |
---|---|
bin | 11110100100100110100… |
… | …010001010001101100001 |
3 | 21102211202022201002021212 |
4 | 132210212202022031201 |
5 | 233410103141343143 |
6 | 4245044455155505 |
7 | 304532621035355 |
oct | 36444642121541 |
9 | 7384668632255 |
10 | 2100885496673 |
11 | 73aa87102717 |
12 | 29b1ba375b95 |
13 | 12316065cc32 |
14 | 7397d373465 |
15 | 399aed2b918 |
hex | 1e92688a361 |
2100885496673 has 2 divisors, whose sum is σ = 2100885496674. Its totient is φ = 2100885496672.
The previous prime is 2100885496613. The next prime is 2100885496727. The reversal of 2100885496673 is 3766945880012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1602206603089 + 498678893584 = 1265783^2 + 706172^2 .
It is a cyclic number.
It is not a de Polignac number, because 2100885496673 - 226 = 2100818387809 is a prime.
It is not a weakly prime, because it can be changed into another prime (2100885496603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1050442748336 + 1050442748337.
It is an arithmetic number, because the mean of its divisors is an integer number (1050442748337).
It is a 1-persistent number, because it is pandigital, but 2⋅2100885496673 = 4201770993346 is not.
Almost surely, 22100885496673 is an apocalyptic number.
It is an amenable number.
2100885496673 is a deficient number, since it is larger than the sum of its proper divisors (1).
2100885496673 is an equidigital number, since it uses as much as digits as its factorization.
2100885496673 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17418240, while the sum is 59.
The spelling of 2100885496673 in words is "two trillion, one hundred billion, eight hundred eighty-five million, four hundred ninety-six thousand, six hundred seventy-three".
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