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21009998953 is a prime number
BaseRepresentation
bin10011100100010010…
…110010010001101001
32000020020000112100101
4103210102302101221
5321012024431303
613352445105401
71342435021156
oct234422622151
960206015311
1021009998953
118a016621a9
1240a4258261
131c9aa06058
1410344b722d
1582e774d1d
hex4e44b2469

21009998953 has 2 divisors, whose sum is σ = 21009998954. Its totient is φ = 21009998952.

The previous prime is 21009998939. The next prime is 21009998987. The reversal of 21009998953 is 35989990012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14248719424 + 6761279529 = 119368^2 + 82227^2 .

It is a cyclic number.

It is not a de Polignac number, because 21009998953 - 229 = 20473128041 is a prime.

It is a super-2 number, since 2×210099989532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21009998894 and 21009998903.

It is not a weakly prime, because it can be changed into another prime (21009998453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10504999476 + 10504999477.

It is an arithmetic number, because the mean of its divisors is an integer number (10504999477).

Almost surely, 221009998953 is an apocalyptic number.

It is an amenable number.

21009998953 is a deficient number, since it is larger than the sum of its proper divisors (1).

21009998953 is an equidigital number, since it uses as much as digits as its factorization.

21009998953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1574640, while the sum is 55.

The spelling of 21009998953 in words is "twenty-one billion, nine million, nine hundred ninety-eight thousand, nine hundred fifty-three".