Base | Representation |
---|---|
bin | 101111110001010111000011… |
… | …111010111000001101010011 |
3 | 1000112220101100022222222210121 |
4 | 233301113003322320031103 |
5 | 210014240203231211011 |
6 | 2022502411143411111 |
7 | 62153144604501412 |
oct | 5761270372701523 |
9 | 1015811308888717 |
10 | 210100202210131 |
11 | 60a42aa4934982 |
12 | 1b6929b0753a97 |
13 | 9030496aa60ac |
14 | 39c4c929ad479 |
15 | 19452c5d60e71 |
hex | bf15c3eb8353 |
210100202210131 has 2 divisors, whose sum is σ = 210100202210132. Its totient is φ = 210100202210130.
The previous prime is 210100202210099. The next prime is 210100202210149. The reversal of 210100202210131 is 131012202001012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 210100202210131 - 25 = 210100202210099 is a prime.
It is a super-3 number, since 3×2101002022101313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (210100202210231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105050101105065 + 105050101105066.
It is an arithmetic number, because the mean of its divisors is an integer number (105050101105066).
Almost surely, 2210100202210131 is an apocalyptic number.
210100202210131 is a deficient number, since it is larger than the sum of its proper divisors (1).
210100202210131 is an equidigital number, since it uses as much as digits as its factorization.
210100202210131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 210100202210131 its reverse (131012202001012), we get a palindrome (341112404211143).
The spelling of 210100202210131 in words is "two hundred ten trillion, one hundred billion, two hundred two million, two hundred ten thousand, one hundred thirty-one".
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