Base | Representation |
---|---|
bin | 1100001110101110110… |
… | …1111010011110010001 |
3 | 202002100010220000001101 |
4 | 3003223231322132101 |
5 | 11420302424040303 |
6 | 240305153104401 |
7 | 21115540661263 |
oct | 3035355723621 |
9 | 662303800041 |
10 | 210113111953 |
11 | 81121412968 |
12 | 3487a558101 |
13 | 16a765912a4 |
14 | a253289b33 |
15 | 56eb226d1d |
hex | 30ebb7a791 |
210113111953 has 2 divisors, whose sum is σ = 210113111954. Its totient is φ = 210113111952.
The previous prime is 210113111947. The next prime is 210113112019. The reversal of 210113111953 is 359111311012.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 206562978064 + 3550133889 = 454492^2 + 59583^2 .
It is a cyclic number.
It is not a de Polignac number, because 210113111953 - 229 = 209576241041 is a prime.
It is a super-5 number, since 5×2101131119535 (a number of 58 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (210113211953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105056555976 + 105056555977.
It is an arithmetic number, because the mean of its divisors is an integer number (105056555977).
Almost surely, 2210113111953 is an apocalyptic number.
It is an amenable number.
210113111953 is a deficient number, since it is larger than the sum of its proper divisors (1).
210113111953 is an equidigital number, since it uses as much as digits as its factorization.
210113111953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 28.
Adding to 210113111953 its reverse (359111311012), we get a palindrome (569224422965).
The spelling of 210113111953 in words is "two hundred ten billion, one hundred thirteen million, one hundred eleven thousand, nine hundred fifty-three".
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