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2102111343401 is a prime number
BaseRepresentation
bin11110100101101111100…
…110011001001100101001
321102221220202100112212112
4132211233212121030221
5233420111000442101
64245410245252105
7304605164413466
oct36455746311451
97387822315775
102102111343401
11740556062493
1229b4a0a04035
131232c7603b24
1473a580b066d
1539a327706bb
hex1e96f999329

2102111343401 has 2 divisors, whose sum is σ = 2102111343402. Its totient is φ = 2102111343400.

The previous prime is 2102111343317. The next prime is 2102111343461. The reversal of 2102111343401 is 1043431112012.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2072877183001 + 29234160400 = 1439749^2 + 170980^2 .

It is a cyclic number.

It is not a de Polignac number, because 2102111343401 - 222 = 2102107149097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2102111343461) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1051055671700 + 1051055671701.

It is an arithmetic number, because the mean of its divisors is an integer number (1051055671701).

Almost surely, 22102111343401 is an apocalyptic number.

It is an amenable number.

2102111343401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2102111343401 is an equidigital number, since it uses as much as digits as its factorization.

2102111343401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2102111343401 its reverse (1043431112012), we get a palindrome (3145542455413).

The spelling of 2102111343401 in words is "two trillion, one hundred two billion, one hundred eleven million, three hundred forty-three thousand, four hundred one".