Base | Representation |
---|---|
bin | 11110100111100010100… |
… | …111111101010001110001 |
3 | 21110010220020121000202122 |
4 | 132213202213331101301 |
5 | 233433034012230134 |
6 | 4250325543324025 |
7 | 305004046354643 |
oct | 36474247752161 |
9 | 7403806530678 |
10 | 2104041133169 |
11 | 741356405068 |
12 | 29b93b150615 |
13 | 123544367a71 |
14 | 73b9c4d0893 |
15 | 39ae6db502e |
hex | 1e9e29fd471 |
2104041133169 has 2 divisors, whose sum is σ = 2104041133170. Its totient is φ = 2104041133168.
The previous prime is 2104041133079. The next prime is 2104041133223. The reversal of 2104041133169 is 9613311404012.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1952321535025 + 151719598144 = 1397255^2 + 389512^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2104041133169 is a prime.
It is a super-2 number, since 2×21040411331692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2104041132169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052020566584 + 1052020566585.
It is an arithmetic number, because the mean of its divisors is an integer number (1052020566585).
Almost surely, 22104041133169 is an apocalyptic number.
It is an amenable number.
2104041133169 is a deficient number, since it is larger than the sum of its proper divisors (1).
2104041133169 is an equidigital number, since it uses as much as digits as its factorization.
2104041133169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 2104041133169 in words is "two trillion, one hundred four billion, forty-one million, one hundred thirty-three thousand, one hundred sixty-nine".
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