Base | Representation |
---|---|
bin | 10011100110010000… |
… | …101110011011100011 |
3 | 2000022112010211120201 |
4 | 103212100232123203 |
5 | 321044002411342 |
6 | 13400024450031 |
7 | 1343315443066 |
oct | 234620563343 |
9 | 60275124521 |
10 | 21043013347 |
11 | 8a19261424 |
12 | 40b3319917 |
13 | 1ca47c50b5 |
14 | 1038a2c8dd |
15 | 8325e6db7 |
hex | 4e642e6e3 |
21043013347 has 2 divisors, whose sum is σ = 21043013348. Its totient is φ = 21043013346.
The previous prime is 21043013339. The next prime is 21043013353. The reversal of 21043013347 is 74331034012.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21043013347 - 23 = 21043013339 is a prime.
It is not a weakly prime, because it can be changed into another prime (21043013377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10521506673 + 10521506674.
It is an arithmetic number, because the mean of its divisors is an integer number (10521506674).
Almost surely, 221043013347 is an apocalyptic number.
21043013347 is a deficient number, since it is larger than the sum of its proper divisors (1).
21043013347 is an equidigital number, since it uses as much as digits as its factorization.
21043013347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 21043013347 its reverse (74331034012), we get a palindrome (95374047359).
The spelling of 21043013347 in words is "twenty-one billion, forty-three million, thirteen thousand, three hundred forty-seven".
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