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21044200055 = 54208840011
BaseRepresentation
bin10011100110010101…
…010000001001110111
32000022121101010102212
4103212111100021313
5321044303400210
613400110124035
71343331514634
oct234625201167
960277333385
1021044200055
118a199a1a7a
1240b37b061b
131ca4b1c2a8
141038c5b18b
1583277d805
hex4e6550277

21044200055 has 4 divisors (see below), whose sum is σ = 25253040072. Its totient is φ = 16835360040.

The previous prime is 21044200033. The next prime is 21044200103. The reversal of 21044200055 is 55000244012.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 21044200055 - 218 = 21043937911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21044200055.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2104420001 + ... + 2104420010.

It is an arithmetic number, because the mean of its divisors is an integer number (6313260018).

Almost surely, 221044200055 is an apocalyptic number.

21044200055 is a deficient number, since it is larger than the sum of its proper divisors (4208840017).

21044200055 is an equidigital number, since it uses as much as digits as its factorization.

21044200055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4208840016.

The product of its (nonzero) digits is 1600, while the sum is 23.

Adding to 21044200055 its reverse (55000244012), we get a palindrome (76044444067).

The spelling of 21044200055 in words is "twenty-one billion, forty-four million, two hundred thousand, fifty-five".

Divisors: 1 5 4208840011 21044200055