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2104931280217 is a prime number
BaseRepresentation
bin11110101000010111101…
…011100110010101011001
321110020012021120011221211
4132220113223212111121
5233441344401431332
64250554142303121
7305035105445563
oct36502753462531
97406167504854
102104931280217
11741772917787
1229bb49287aa1
131236568c17ac
1473c44804333
1539b4a0e7447
hex1ea17ae6559

2104931280217 has 2 divisors, whose sum is σ = 2104931280218. Its totient is φ = 2104931280216.

The previous prime is 2104931280211. The next prime is 2104931280253. The reversal of 2104931280217 is 7120821394012.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2012962226521 + 91969053696 = 1418789^2 + 303264^2 .

It is a cyclic number.

It is not a de Polignac number, because 2104931280217 - 219 = 2104930755929 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2104931280217.

It is not a weakly prime, because it can be changed into another prime (2104931280211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1052465640108 + 1052465640109.

It is an arithmetic number, because the mean of its divisors is an integer number (1052465640109).

Almost surely, 22104931280217 is an apocalyptic number.

It is an amenable number.

2104931280217 is a deficient number, since it is larger than the sum of its proper divisors (1).

2104931280217 is an equidigital number, since it uses as much as digits as its factorization.

2104931280217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 40.

The spelling of 2104931280217 in words is "two trillion, one hundred four billion, nine hundred thirty-one million, two hundred eighty thousand, two hundred seventeen".