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211000121 is a prime number
BaseRepresentation
bin11001001001110…
…01101100111001
3112201000220202022
430210321230321
5413004000441
632534244225
75141320463
oct1444715471
9481026668
10211000121
11a9116572
125a7b6675
1334939157
1420047133
15137cd84b
hexc939b39

211000121 has 2 divisors, whose sum is σ = 211000122. Its totient is φ = 211000120.

The previous prime is 211000109. The next prime is 211000151. The reversal of 211000121 is 121000112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 160376896 + 50623225 = 12664^2 + 7115^2 .

It is a cyclic number.

It is not a de Polignac number, because 211000121 - 210 = 210999097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211000099 and 211000108.

It is not a weakly prime, because it can be changed into another prime (211000151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105500060 + 105500061.

It is an arithmetic number, because the mean of its divisors is an integer number (105500061).

Almost surely, 2211000121 is an apocalyptic number.

It is an amenable number.

211000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

211000121 is an equidigital number, since it uses as much as digits as its factorization.

211000121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 8.

The square root of 211000121 is about 14525.8432113251. The cubic root of 211000121 is about 595.3342951139.

Adding to 211000121 its reverse (121000112), we get a palindrome (332000233).

Subtracting from 211000121 its reverse (121000112), we obtain a palindrome (90000009).

The spelling of 211000121 in words is "two hundred eleven million, one hundred twenty-one", and thus it is an aban number.