Base | Representation |
---|---|
bin | 11110101101000101110… |
… | …111111000101010000011 |
3 | 21110201021121112211011202 |
4 | 132231011313320222003 |
5 | 234032240303021402 |
6 | 4253153212531415 |
7 | 305304540310025 |
oct | 36550567705203 |
9 | 7421247484152 |
10 | 2110001220227 |
11 | 74393475474a |
12 | 2a0b23180b6b |
13 | 123c8409a7b4 |
14 | 741a5cb0015 |
15 | 39d45266b02 |
hex | 1eb45df8a83 |
2110001220227 has 2 divisors, whose sum is σ = 2110001220228. Its totient is φ = 2110001220226.
The previous prime is 2110001220211. The next prime is 2110001220241. The reversal of 2110001220227 is 7220221000112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2110001220227 - 24 = 2110001220211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2110001220199 and 2110001220208.
It is not a weakly prime, because it can be changed into another prime (2110001228227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055000610113 + 1055000610114.
It is an arithmetic number, because the mean of its divisors is an integer number (1055000610114).
Almost surely, 22110001220227 is an apocalyptic number.
2110001220227 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110001220227 is an equidigital number, since it uses as much as digits as its factorization.
2110001220227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 2110001220227 its reverse (7220221000112), we get a palindrome (9330222220339).
The spelling of 2110001220227 in words is "two trillion, one hundred ten billion, one million, two hundred twenty thousand, two hundred twenty-seven".
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