Base | Representation |
---|---|
bin | 11110101101000110011… |
… | …101001100010011010001 |
3 | 21110201022021221200112012 |
4 | 132231012131030103101 |
5 | 234032300304000032 |
6 | 4253154202312305 |
7 | 305305016401364 |
oct | 36550635142321 |
9 | 7421267850465 |
10 | 2110011000017 |
11 | 74393a224418 |
12 | 2a0b264b8695 |
13 | 123c8611305b |
14 | 741a72d80db |
15 | 39d460496b2 |
hex | 1eb4674c4d1 |
2110011000017 has 2 divisors, whose sum is σ = 2110011000018. Its totient is φ = 2110011000016.
The previous prime is 2110010999963. The next prime is 2110011000143. The reversal of 2110011000017 is 7100001100112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1752952168081 + 357058831936 = 1323991^2 + 597544^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110011000017 - 210 = 2110010998993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2110010999965 and 2110011000010.
It is not a weakly prime, because it can be changed into another prime (2110011009017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055005500008 + 1055005500009.
It is an arithmetic number, because the mean of its divisors is an integer number (1055005500009).
Almost surely, 22110011000017 is an apocalyptic number.
It is an amenable number.
2110011000017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110011000017 is an equidigital number, since it uses as much as digits as its factorization.
2110011000017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 2110011000017 its reverse (7100001100112), we get a palindrome (9210012100129).
The spelling of 2110011000017 in words is "two trillion, one hundred ten billion, eleven million, seventeen", and thus it is an aban number.
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