211002044131 has 2 divisors, whose sum is σ = 211002044132. Its totient is φ = 211002044130.

The previous prime is 211002044101. The next prime is 211002044171. The reversal of 211002044131 is 131440200112.

211002044131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211002044131 - 2¹⁹ = 211001519843 is a prime.

It is a super-2 number, since 2×211002044131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211002044099 and 211002044108.

It is not a weakly prime, because it can be changed into another prime (211002044101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105501022065 + 105501022066.

It is an arithmetic number, because the mean of its divisors is an integer number (105501022066).

Almost surely, 2^211002044131 is an apocalyptic number.

211002044131 is a deficient number, since it is larger than the sum of its proper divisors (1).

211002044131 is an equidigital number, since it uses as much as digits as its factorization.

211002044131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 211002044131 its reverse (131440200112), we get a palindrome (342442244243).

The spelling of 211002044131 in words is "two hundred eleven billion, two million, forty-four thousand, one hundred thirty-one".