Base | Representation |
---|---|
bin | 11110101101000111110… |
… | …001000111111000100001 |
3 | 21110201100211100111121002 |
4 | 132231013301013320201 |
5 | 234032321422031032 |
6 | 4253200310041345 |
7 | 305305404406223 |
oct | 36550761077041 |
9 | 7421324314532 |
10 | 2110033002017 |
11 | 743950691896 |
12 | 2a0b31949255 |
13 | 123c8a8477a5 |
14 | 741aa1c4413 |
15 | 39d47e43862 |
hex | 1eb47c47e21 |
2110033002017 has 2 divisors, whose sum is σ = 2110033002018. Its totient is φ = 2110033002016.
The previous prime is 2110033001987. The next prime is 2110033002029. The reversal of 2110033002017 is 7102003300112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2084685496336 + 25347505681 = 1443844^2 + 159209^2 .
It is a cyclic number.
It is not a de Polignac number, because 2110033002017 - 28 = 2110033001761 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2110033002017.
It is not a weakly prime, because it can be changed into another prime (2110033002037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055016501008 + 1055016501009.
It is an arithmetic number, because the mean of its divisors is an integer number (1055016501009).
Almost surely, 22110033002017 is an apocalyptic number.
It is an amenable number.
2110033002017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110033002017 is an equidigital number, since it uses as much as digits as its factorization.
2110033002017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 2110033002017 its reverse (7102003300112), we get a palindrome (9212036302129).
The spelling of 2110033002017 in words is "two trillion, one hundred ten billion, thirty-three million, two thousand, seventeen".
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