Base | Representation |
---|---|
bin | 1100010010000100101… |
… | …1010110001100011010 |
3 | 202011122122120122202110 |
4 | 3010201023112030122 |
5 | 11424122031120442 |
6 | 240534153013150 |
7 | 21150011402016 |
oct | 3044113261432 |
9 | 664578518673 |
10 | 211010020122 |
11 | 81541723290 |
12 | 34a8a9b41b6 |
13 | 16b8a344595 |
14 | a2da43d546 |
15 | 574ed4269c |
hex | 31212d631a |
211010020122 has 16 divisors (see below), whose sum is σ = 460385498592. Its totient is φ = 63942430320.
The previous prime is 211010020103. The next prime is 211010020171. The reversal of 211010020122 is 221020010112.
It is a super-3 number, since 3×2110100201223 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211010020098 and 211010020107.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1598560693 + ... + 1598560824.
It is an arithmetic number, because the mean of its divisors is an integer number (28774093662).
Almost surely, 2211010020122 is an apocalyptic number.
211010020122 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
211010020122 is an abundant number, since it is smaller than the sum of its proper divisors (249375478470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211010020122 is a wasteful number, since it uses less digits than its factorization.
211010020122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3197121533.
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 211010020122 its reverse (221020010112), we get a palindrome (432030030234).
The spelling of 211010020122 in words is "two hundred eleven billion, ten million, twenty thousand, one hundred twenty-two".
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