21101100110113 has 2 divisors, whose sum is σ = 21101100110114. Its totient is φ = 21101100110112.

The previous prime is 21101100110071. The next prime is 21101100110159. The reversal of 21101100110113 is 31101100110112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15094522617889 + 6006577492224 = 3885167^2 + 2450832^2 .

It is a cyclic number.

It is not a de Polignac number, because 21101100110113 - 2⁴¹ = 18902076854561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21101100110093 and 21101100110102.

It is not a weakly prime, because it can be changed into another prime (21101100110173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550550055056 + 10550550055057.

It is an arithmetic number, because the mean of its divisors is an integer number (10550550055057).

Almost surely, 2^{21101100110113} is an apocalyptic number.

It is an amenable number.

21101100110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101100110113 is an equidigital number, since it uses as much as digits as its factorization.

21101100110113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 21101100110113 its reverse (31101100110112), we get a palindrome (52202200220225).

Subtracting 21101100110113 from its reverse (31101100110112), we obtain a palindrome (9999999999999).

The spelling of 21101100110113 in words is "twenty-one trillion, one hundred one billion, one hundred million, one hundred ten thousand, one hundred thirteen".