Base | Representation |
---|---|
bin | 101111111110100111010011… |
… | …110001010101100010000011 |
3 | 1000200010110021111000011022111 |
4 | 233332213103301111202003 |
5 | 210124201012302223021 |
6 | 2024441040555120151 |
7 | 62306020214326501 |
oct | 5776472361254203 |
9 | 1020113244004274 |
10 | 211011001211011 |
11 | 61264299157991 |
12 | 1b7bb419443057 |
13 | 9098337942841 |
14 | 3a16db62a3671 |
15 | 195dd314768e1 |
hex | bfe9d3c55883 |
211011001211011 has 2 divisors, whose sum is σ = 211011001211012. Its totient is φ = 211011001211010.
The previous prime is 211011001210951. The next prime is 211011001211027. The reversal of 211011001211011 is 110112100110112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211011001211011 - 27 = 211011001210883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211011001210982 and 211011001211000.
It is not a weakly prime, because it can be changed into another prime (211011001211071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105505500605505 + 105505500605506.
It is an arithmetic number, because the mean of its divisors is an integer number (105505500605506).
Almost surely, 2211011001211011 is an apocalyptic number.
211011001211011 is a deficient number, since it is larger than the sum of its proper divisors (1).
211011001211011 is an equidigital number, since it uses as much as digits as its factorization.
211011001211011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 211011001211011 its reverse (110112100110112), we get a palindrome (321123101321123).
The spelling of 211011001211011 in words is "two hundred eleven trillion, eleven billion, one million, two hundred eleven thousand, eleven".
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