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21101130244147 is a prime number
BaseRepresentation
bin1001100110000111111010…
…10111110110000000110011
32202201020201001021121212211
410303003331113312000303
510231210103320303042
6112513420404432551
74305335451455602
oct463037527660063
982636631247784
1021101130244147
1167a5a36a101a8
1224496599a8757
13ba0a9c29bb15
1452d42b897a39
15268d4eb94017
hex1330fd5f6033

21101130244147 has 2 divisors, whose sum is σ = 21101130244148. Its totient is φ = 21101130244146.

The previous prime is 21101130244121. The next prime is 21101130244169. The reversal of 21101130244147 is 74144203110112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21101130244147 is a prime.

It is not a weakly prime, because it can be changed into another prime (21101130244547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550565122073 + 10550565122074.

It is an arithmetic number, because the mean of its divisors is an integer number (10550565122074).

Almost surely, 221101130244147 is an apocalyptic number.

21101130244147 is a deficient number, since it is larger than the sum of its proper divisors (1).

21101130244147 is an equidigital number, since it uses as much as digits as its factorization.

21101130244147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 31.

Adding to 21101130244147 its reverse (74144203110112), we get a palindrome (95245333354259).

The spelling of 21101130244147 in words is "twenty-one trillion, one hundred one billion, one hundred thirty million, two hundred forty-four thousand, one hundred forty-seven".