Base | Representation |
---|---|
bin | 1001100110001000000001… |
… | …00011111100100100111001 |
3 | 2202201020211202221220221011 |
4 | 10303010000203330210321 |
5 | 10231210211014422114 |
6 | 112513425555313521 |
7 | 4305340001316652 |
oct | 463040043744471 |
9 | 82636752856834 |
10 | 21101183748409 |
11 | 67a5a641347a6 |
12 | 24496738ab8a1 |
13 | ba0aaa3b324b |
14 | 52d434a24529 |
15 | 268d547121c4 |
hex | 1331008fc939 |
21101183748409 has 2 divisors, whose sum is σ = 21101183748410. Its totient is φ = 21101183748408.
The previous prime is 21101183748391. The next prime is 21101183748451. The reversal of 21101183748409 is 90484738110112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18188007267600 + 2913176480809 = 4264740^2 + 1706803^2 .
It is a cyclic number.
It is not a de Polignac number, because 21101183748409 - 215 = 21101183715641 is a prime.
It is not a weakly prime, because it can be changed into another prime (21101183748509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10550591874204 + 10550591874205.
It is an arithmetic number, because the mean of its divisors is an integer number (10550591874205).
Almost surely, 221101183748409 is an apocalyptic number.
It is an amenable number.
21101183748409 is a deficient number, since it is larger than the sum of its proper divisors (1).
21101183748409 is an equidigital number, since it uses as much as digits as its factorization.
21101183748409 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 49.
The spelling of 21101183748409 in words is "twenty-one trillion, one hundred one billion, one hundred eighty-three million, seven hundred forty-eight thousand, four hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •