Base | Representation |
---|---|
bin | 111110111000101… |
… | …1110000100010101 |
3 | 12110001120012202111 |
4 | 1331301132010111 |
5 | 13310142321323 |
6 | 545215111021 |
7 | 103201503655 |
oct | 17561360425 |
9 | 5401505674 |
10 | 2110120213 |
11 | 993120603 |
12 | 4aa812471 |
13 | 278222356 |
14 | 160362365 |
15 | c53b5c0d |
hex | 7dc5e115 |
2110120213 has 4 divisors (see below), whose sum is σ = 2139840288. Its totient is φ = 2080400140.
The previous prime is 2110120163. The next prime is 2110120231. The reversal of 2110120213 is 3120210112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2110120213 - 213 = 2110112021 is a prime.
It is a super-2 number, since 2×21101202132 = 8905214626622330738, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2110120193 and 2110120202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2110120253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14859931 + ... + 14860072.
It is an arithmetic number, because the mean of its divisors is an integer number (534960072).
Almost surely, 22110120213 is an apocalyptic number.
It is an amenable number.
2110120213 is a deficient number, since it is larger than the sum of its proper divisors (29720075).
2110120213 is an equidigital number, since it uses as much as digits as its factorization.
2110120213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29720074.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 2110120213 is about 45936.0448123258. The cubic root of 2110120213 is about 1282.6329699359.
Adding to 2110120213 its reverse (3120210112), we get a palindrome (5230330325).
It can be divided in two parts, 21101 and 20213, that added together give a palindrome (41314).
The spelling of 2110120213 in words is "two billion, one hundred ten million, one hundred twenty thousand, two hundred thirteen".
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