Base | Representation |
---|---|
bin | 1100010010000101001… |
… | …1010001111110000111 |
3 | 202011122210111022210001 |
4 | 3010201103101332013 |
5 | 11424123044144400 |
6 | 240534305342131 |
7 | 21150035153515 |
oct | 3044123217607 |
9 | 664583438701 |
10 | 211012099975 |
11 | 81542913976 |
12 | 34a8b637947 |
13 | 16b8a8c2171 |
14 | a2da8214b5 |
15 | 5750103a6a |
hex | 31214d1f87 |
211012099975 has 12 divisors (see below), whose sum is σ = 261743225040. Its totient is φ = 168752763200.
The previous prime is 211012099957. The next prime is 211012099979. The reversal of 211012099975 is 579990210112.
It is not a de Polignac number, because 211012099975 - 211 = 211012097927 is a prime.
It is a super-2 number, since 2×2110120999752 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211012099979) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1347211 + ... + 1495660.
It is an arithmetic number, because the mean of its divisors is an integer number (21811935420).
Almost surely, 2211012099975 is an apocalyptic number.
211012099975 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
211012099975 is a deficient number, since it is larger than the sum of its proper divisors (50731125065).
211012099975 is a wasteful number, since it uses less digits than its factorization.
211012099975 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2845850 (or 2845845 counting only the distinct ones).
The product of its (nonzero) digits is 102060, while the sum is 46.
The spelling of 211012099975 in words is "two hundred eleven billion, twelve million, ninety-nine thousand, nine hundred seventy-five".
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