211012101433 has 32 divisors (see below), whose sum is σ = 249426777600. Its totient is φ = 178418580480.

The previous prime is 211012101403. The next prime is 211012101457. The reversal of 211012101433 is 334101210112.

It is not a de Polignac number, because 211012101433 - 2¹⁷ = 211011970361 is a prime.

It is a super-2 number, since 2×211012101433² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211012101433.

It is not an unprimeable number, because it can be changed into a prime (211012101403) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10337085 + ... + 10357477.

It is an arithmetic number, because the mean of its divisors is an integer number (7794586800).

Almost surely, 2^211012101433 is an apocalyptic number.

It is an amenable number.

211012101433 is a deficient number, since it is larger than the sum of its proper divisors (38414676167).

211012101433 is an equidigital number, since it uses as much as digits as its factorization.

211012101433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20822 (or 20808 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 211012101433 its reverse (334101210112), we get a palindrome (545113311545).

It can be divided in two parts, 211012 and 101433, that added together give a triangular number (312445 = T₇₉₀).

The spelling of 211012101433 in words is "two hundred eleven billion, twelve million, one hundred one thousand, four hundred thirty-three".