Base | Representation |
---|---|
bin | 11110101101001101000… |
… | …101011001011111101001 |
3 | 21110201121001012101111101 |
4 | 132231031011121133221 |
5 | 234033012240444423 |
6 | 4253213214001401 |
7 | 305310536533561 |
oct | 36551505313751 |
9 | 7421531171441 |
10 | 2110122203113 |
11 | 743996a77a01 |
12 | 2a0b577a6261 |
13 | 123ca3179bc2 |
14 | 741b7da3da1 |
15 | 39d50bb37ad |
hex | 1eb4d1597e9 |
2110122203113 has 2 divisors, whose sum is σ = 2110122203114. Its totient is φ = 2110122203112.
The previous prime is 2110122203051. The next prime is 2110122203219. The reversal of 2110122203113 is 3113022210112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2104974427609 + 5147775504 = 1450853^2 + 71748^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2110122203113 is a prime.
It is not a weakly prime, because it can be changed into another prime (2110122206113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055061101556 + 1055061101557.
It is an arithmetic number, because the mean of its divisors is an integer number (1055061101557).
Almost surely, 22110122203113 is an apocalyptic number.
It is an amenable number.
2110122203113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110122203113 is an equidigital number, since it uses as much as digits as its factorization.
2110122203113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2110122203113 its reverse (3113022210112), we get a palindrome (5223144413225).
The spelling of 2110122203113 in words is "two trillion, one hundred ten billion, one hundred twenty-two million, two hundred three thousand, one hundred thirteen".
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