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2110122203113 is a prime number
BaseRepresentation
bin11110101101001101000…
…101011001011111101001
321110201121001012101111101
4132231031011121133221
5234033012240444423
64253213214001401
7305310536533561
oct36551505313751
97421531171441
102110122203113
11743996a77a01
122a0b577a6261
13123ca3179bc2
14741b7da3da1
1539d50bb37ad
hex1eb4d1597e9

2110122203113 has 2 divisors, whose sum is σ = 2110122203114. Its totient is φ = 2110122203112.

The previous prime is 2110122203051. The next prime is 2110122203219. The reversal of 2110122203113 is 3113022210112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2104974427609 + 5147775504 = 1450853^2 + 71748^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2110122203113 is a prime.

It is not a weakly prime, because it can be changed into another prime (2110122206113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055061101556 + 1055061101557.

It is an arithmetic number, because the mean of its divisors is an integer number (1055061101557).

Almost surely, 22110122203113 is an apocalyptic number.

It is an amenable number.

2110122203113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2110122203113 is an equidigital number, since it uses as much as digits as its factorization.

2110122203113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2110122203113 its reverse (3113022210112), we get a palindrome (5223144413225).

The spelling of 2110122203113 in words is "two trillion, one hundred ten billion, one hundred twenty-two million, two hundred three thousand, one hundred thirteen".