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21102001121323 is a prime number
BaseRepresentation
bin1001100110001001100010…
…10001111110100000101011
32202201022221201222202210001
410303010301101332200223
510231213344241340243
6112514043034403431
74305366155011243
oct463046121764053
982638851882701
1021102001121323
1167a6343561101
122449861590577
13ba0baa839865
1452d4b13d2b23
15268da136ba4d
hex13313147e82b

21102001121323 has 2 divisors, whose sum is σ = 21102001121324. Its totient is φ = 21102001121322.

The previous prime is 21102001121213. The next prime is 21102001121413. The reversal of 21102001121323 is 32312110020112.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21102001121323 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21102001121323.

It is not a weakly prime, because it can be changed into another prime (21102001121023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551000560661 + 10551000560662.

It is an arithmetic number, because the mean of its divisors is an integer number (10551000560662).

Almost surely, 221102001121323 is an apocalyptic number.

21102001121323 is a deficient number, since it is larger than the sum of its proper divisors (1).

21102001121323 is an equidigital number, since it uses as much as digits as its factorization.

21102001121323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 21102001121323 its reverse (32312110020112), we get a palindrome (53414111141435).

The spelling of 21102001121323 in words is "twenty-one trillion, one hundred two billion, one million, one hundred twenty-one thousand, three hundred twenty-three".