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21102110113 = 75356879003
BaseRepresentation
bin10011101001110010…
…001010010110100001
32000110122100021002211
4103221302022112201
5321204120010423
613405535242121
71344633655630
oct235162122641
960418307084
1021102110113
118a49655727
12410b079341
131cb3b16bb6
141042813517
158378bc10d
hex4e9c8a5a1

21102110113 has 8 divisors (see below), whose sum is σ = 24571729728. Its totient is φ = 17746248624.

The previous prime is 21102110039. The next prime is 21102110123. The reversal of 21102110113 is 31101120112.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21102110113 - 225 = 21068555681 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21102110093 and 21102110102.

It is not an unprimeable number, because it can be changed into a prime (21102110123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28439131 + ... + 28439872.

It is an arithmetic number, because the mean of its divisors is an integer number (3071466216).

Almost surely, 221102110113 is an apocalyptic number.

It is an amenable number.

21102110113 is a deficient number, since it is larger than the sum of its proper divisors (3469619615).

21102110113 is an equidigital number, since it uses as much as digits as its factorization.

21102110113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56879063.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 21102110113 its reverse (31101120112), we get a palindrome (52203230225).

Subtracting 21102110113 from its reverse (31101120112), we obtain a palindrome (9999009999).

The spelling of 21102110113 in words is "twenty-one billion, one hundred two million, one hundred ten thousand, one hundred thirteen".

Divisors: 1 7 53 371 56879003 398153021 3014587159 21102110113