211021134000113 has 2 divisors, whose sum is σ = 211021134000114. Its totient is φ = 211021134000112.

The previous prime is 211021134000109. The next prime is 211021134000169. The reversal of 211021134000113 is 311000431120112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 152081381008384 + 58939752991729 = 12332128^2 + 7677223^2 .

It is a cyclic number.

It is not a de Polignac number, because 211021134000113 - 2² = 211021134000109 is a prime.

It is not a weakly prime, because it can be changed into another prime (211021134000913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105510567000056 + 105510567000057.

It is an arithmetic number, because the mean of its divisors is an integer number (105510567000057).

Almost surely, 2^{211021134000113} is an apocalyptic number.

It is an amenable number.

211021134000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211021134000113 is an equidigital number, since it uses as much as digits as its factorization.

211021134000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 211021134000113 its reverse (311000431120112), we get a palindrome (522021565120225).

The spelling of 211021134000113 in words is "two hundred eleven trillion, twenty-one billion, one hundred thirty-four million, one hundred thirteen", and thus it is an aban number.