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21102121153 is a prime number
BaseRepresentation
bin10011101001110010…
…001101000011000001
32000110122100211020201
4103221302031003001
5321204120334103
613405535405201
71344634033051
oct235162150301
960418324221
1021102121153
118a49662a53
12410b083801
131cb3b1bc29
141042817561
158378c051d
hex4e9c8d0c1

21102121153 has 2 divisors, whose sum is σ = 21102121154. Its totient is φ = 21102121152.

The previous prime is 21102121141. The next prime is 21102121217. The reversal of 21102121153 is 35112120112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19502681104 + 1599440049 = 139652^2 + 39993^2 .

It is a cyclic number.

It is not a de Polignac number, because 21102121153 - 229 = 20565250241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21102121153.

It is not a weakly prime, because it can be changed into another prime (21102121123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551060576 + 10551060577.

It is an arithmetic number, because the mean of its divisors is an integer number (10551060577).

Almost surely, 221102121153 is an apocalyptic number.

It is an amenable number.

21102121153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21102121153 is an equidigital number, since it uses as much as digits as its factorization.

21102121153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 21102121153 its reverse (35112120112), we get a palindrome (56214241265).

The spelling of 21102121153 in words is "twenty-one billion, one hundred two million, one hundred twenty-one thousand, one hundred fifty-three".