Base | Representation |
---|---|
bin | 1100010010001001011… |
… | …1111111101101101011 |
3 | 202011201001101111011222 |
4 | 3010202113333231223 |
5 | 11424142202110011 |
6 | 240540151412255 |
7 | 21150344236145 |
oct | 3044227775553 |
9 | 664631344158 |
10 | 211030113131 |
11 | 81551aa7482 |
12 | 34a9568408b |
13 | 16b9155b136 |
14 | a2dcd8dc95 |
15 | 57519b0ddb |
hex | 31225ffb6b |
211030113131 has 2 divisors, whose sum is σ = 211030113132. Its totient is φ = 211030113130.
The previous prime is 211030113109. The next prime is 211030113157. The reversal of 211030113131 is 131311030112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211030113131 - 214 = 211030096747 is a prime.
It is a super-2 number, since 2×2110301131312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211030113331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105515056565 + 105515056566.
It is an arithmetic number, because the mean of its divisors is an integer number (105515056566).
Almost surely, 2211030113131 is an apocalyptic number.
211030113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211030113131 is an equidigital number, since it uses as much as digits as its factorization.
211030113131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 211030113131 its reverse (131311030112), we get a palindrome (342341143243).
The spelling of 211030113131 in words is "two hundred eleven billion, thirty million, one hundred thirteen thousand, one hundred thirty-one".
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