Base | Representation |
---|---|
bin | 1100010010001001100… |
… | …0111011010010110011 |
3 | 202011201001211212221111 |
4 | 3010202120323102303 |
5 | 11424142232412141 |
6 | 240540200534151 |
7 | 21150346303504 |
oct | 3044230732263 |
9 | 664631755844 |
10 | 211030357171 |
11 | 81552153867 |
12 | 34a95781357 |
13 | 16b9161523a |
14 | a2dd014bab |
15 | 5751a0d381 |
hex | 312263b4b3 |
211030357171 has 2 divisors, whose sum is σ = 211030357172. Its totient is φ = 211030357170.
The previous prime is 211030357117. The next prime is 211030357231. The reversal of 211030357171 is 171753030112.
Together with previous prime (211030357117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211030357171 - 213 = 211030348979 is a prime.
It is a super-3 number, since 3×2110303571713 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (211030157171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105515178585 + 105515178586.
It is an arithmetic number, because the mean of its divisors is an integer number (105515178586).
Almost surely, 2211030357171 is an apocalyptic number.
211030357171 is a deficient number, since it is larger than the sum of its proper divisors (1).
211030357171 is an equidigital number, since it uses as much as digits as its factorization.
211030357171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4410, while the sum is 31.
Adding to 211030357171 its reverse (171753030112), we get a palindrome (382783387283).
The spelling of 211030357171 in words is "two hundred eleven billion, thirty million, three hundred fifty-seven thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •