Base | Representation |
---|---|
bin | 1001100110001011100101… |
… | …10101101011101001111001 |
3 | 2202201102210101121102002221 |
4 | 10303011302311223221321 |
5 | 10231223122324002223 |
6 | 112514344124524041 |
7 | 4305435341561443 |
oct | 463056265535171 |
9 | 82642711542087 |
10 | 21103101000313 |
11 | 67a68583a3502 |
12 | 2449b099b0621 |
13 | ba1024677427 |
14 | 52d5774dd493 |
15 | 268e17bcbb5d |
hex | 133172d6ba79 |
21103101000313 has 2 divisors, whose sum is σ = 21103101000314. Its totient is φ = 21103101000312.
The previous prime is 21103101000253. The next prime is 21103101000361. The reversal of 21103101000313 is 31300010130112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18338290276329 + 2764810723984 = 4282323^2 + 1662772^2 .
It is a cyclic number.
It is not a de Polignac number, because 21103101000313 - 29 = 21103100999801 is a prime.
It is not a weakly prime, because it can be changed into another prime (21103101000383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10551550500156 + 10551550500157.
It is an arithmetic number, because the mean of its divisors is an integer number (10551550500157).
Almost surely, 221103101000313 is an apocalyptic number.
It is an amenable number.
21103101000313 is a deficient number, since it is larger than the sum of its proper divisors (1).
21103101000313 is an equidigital number, since it uses as much as digits as its factorization.
21103101000313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 21103101000313 its reverse (31300010130112), we get a palindrome (52403111130425).
The spelling of 21103101000313 in words is "twenty-one trillion, one hundred three billion, one hundred one million, three hundred thirteen", and thus it is an aban number.
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