Base | Representation |
---|---|
bin | 101111111110111011111110… |
… | …111111100111111010000001 |
3 | 1000200012120120122020010000111 |
4 | 233332323332333213322001 |
5 | 210130031444002304212 |
6 | 2024455151514151321 |
7 | 62310434312251516 |
oct | 5776737677477201 |
9 | 1020176518203014 |
10 | 211033201213057 |
11 | 61272750508013 |
12 | 1b803794122541 |
13 | 909a46504ca22 |
14 | 3a180c082730d |
15 | 195e6d040eea7 |
hex | bfeefefe7e81 |
211033201213057 has 2 divisors, whose sum is σ = 211033201213058. Its totient is φ = 211033201213056.
The previous prime is 211033201212997. The next prime is 211033201213171. The reversal of 211033201213057 is 750312102330112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 209676887090176 + 1356314122881 = 14480224^2 + 1164609^2 .
It is a cyclic number.
It is not a de Polignac number, because 211033201213057 - 223 = 211033192824449 is a prime.
It is not a weakly prime, because it can be changed into another prime (211033201213957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105516600606528 + 105516600606529.
It is an arithmetic number, because the mean of its divisors is an integer number (105516600606529).
Almost surely, 2211033201213057 is an apocalyptic number.
It is an amenable number.
211033201213057 is a deficient number, since it is larger than the sum of its proper divisors (1).
211033201213057 is an equidigital number, since it uses as much as digits as its factorization.
211033201213057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 211033201213057 its reverse (750312102330112), we get a palindrome (961345303543169).
The spelling of 211033201213057 in words is "two hundred eleven trillion, thirty-three billion, two hundred one million, two hundred thirteen thousand, fifty-seven".
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