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2110413401111 = 7392855769149
BaseRepresentation
bin11110101101011110011…
…100001110110000010111
321110202100100010210001102
4132231132130032300113
5234034111312313421
64253302135220315
7305321003633411
oct36553634166027
97422310123042
102110413401111
1174402638a304
122a101921769b
1312401b5b5502
14742049259b1
1539d6b53460b
hex1eb5e70ec17

2110413401111 has 4 divisors (see below), whose sum is σ = 2113269171000. Its totient is φ = 2107557631224.

The previous prime is 2110413401053. The next prime is 2110413401113. The reversal of 2110413401111 is 1111043140112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2110413401111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2110413401113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1427883836 + ... + 1427885313.

It is an arithmetic number, because the mean of its divisors is an integer number (528317292750).

Almost surely, 22110413401111 is an apocalyptic number.

2110413401111 is a deficient number, since it is larger than the sum of its proper divisors (2855769889).

2110413401111 is an equidigital number, since it uses as much as digits as its factorization.

2110413401111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2855769888.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 2110413401111 its reverse (1111043140112), we get a palindrome (3221456541223).

The spelling of 2110413401111 in words is "two trillion, one hundred ten billion, four hundred thirteen million, four hundred one thousand, one hundred eleven".

Divisors: 1 739 2855769149 2110413401111