Base | Representation |
---|---|
bin | 101111111111000101100000… |
… | …111011111101001100101111 |
3 | 1000200020112222210200111122102 |
4 | 233333011200323331030233 |
5 | 210130213423143302310 |
6 | 2024504003150005315 |
7 | 62311246020436214 |
oct | 5777054073751457 |
9 | 1020215883614572 |
10 | 211043434353455 |
11 | 6127702188a940 |
12 | 1b80576b1a683b |
13 | 909b4061289a2 |
14 | 3a187b1917b0b |
15 | 195eacd9c18a5 |
hex | bff160efd32f |
211043434353455 has 16 divisors (see below), whose sum is σ = 276279055105824. Its totient is φ = 153483904202880.
The previous prime is 211043434353397. The next prime is 211043434353509. The reversal of 211043434353455 is 554353434340112.
It is not a de Polignac number, because 211043434353455 - 210 = 211043434352431 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24048512 + ... + 31629381.
It is an arithmetic number, because the mean of its divisors is an integer number (17267440944114).
Almost surely, 2211043434353455 is an apocalyptic number.
211043434353455 is a deficient number, since it is larger than the sum of its proper divisors (65235620752369).
211043434353455 is a wasteful number, since it uses less digits than its factorization.
211043434353455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55746826.
The product of its (nonzero) digits is 5184000, while the sum is 47.
Adding to 211043434353455 its reverse (554353434340112), we get a palindrome (765396868693567).
The spelling of 211043434353455 in words is "two hundred eleven trillion, forty-three billion, four hundred thirty-four million, three hundred fifty-three thousand, four hundred fifty-five".
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