Base | Representation |
---|---|
bin | 11110101110000001011… |
… | …110100010110010011011 |
3 | 21110210212022012120021102 |
4 | 132232001132202302123 |
5 | 234041312302210021 |
6 | 4253440334102015 |
7 | 305341402136111 |
oct | 36560136426233 |
9 | 7423768176242 |
10 | 2111001210011 |
11 | 7442a8170891 |
12 | 2a116204a90b |
13 | 1240b3303125 |
14 | 7425ca17ab1 |
15 | 39da2e4500b |
hex | 1eb817a2c9b |
2111001210011 has 2 divisors, whose sum is σ = 2111001210012. Its totient is φ = 2111001210010.
The previous prime is 2111001209963. The next prime is 2111001210053. The reversal of 2111001210011 is 1100121001112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2111001210011 - 222 = 2110997015707 is a prime.
It is a super-2 number, since 2×21110012100112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2111001209974 and 2111001210001.
It is not a weakly prime, because it can be changed into another prime (2111001240011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055500605005 + 1055500605006.
It is an arithmetic number, because the mean of its divisors is an integer number (1055500605006).
Almost surely, 22111001210011 is an apocalyptic number.
2111001210011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111001210011 is an equidigital number, since it uses as much as digits as its factorization.
2111001210011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 2111001210011 its reverse (1100121001112), we get a palindrome (3211122211123).
The spelling of 2111001210011 in words is "two trillion, one hundred eleven billion, one million, two hundred ten thousand, eleven".
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