Base | Representation |
---|---|
bin | 11110101110000001100… |
… | …001100110110101001010 |
3 | 21110210212100201100202211 |
4 | 132232001201212311022 |
5 | 234041313003404002 |
6 | 4253440403215334 |
7 | 305341412022151 |
oct | 36560141466512 |
9 | 7423770640684 |
10 | 2111002013002 |
11 | 7442a866a113 |
12 | 2a116237754a |
13 | 1240b352477c |
14 | 7425cb86598 |
15 | 39da3052dd7 |
hex | 1eb81866d4a |
2111002013002 has 4 divisors (see below), whose sum is σ = 3166503019506. Its totient is φ = 1055501006500.
The previous prime is 2111002012943. The next prime is 2111002013059. The reversal of 2111002013002 is 2003102001112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1405554884721 + 705447128281 = 1185561^2 + 839909^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527750503249 + ... + 527750503252.
Almost surely, 22111002013002 is an apocalyptic number.
2111002013002 is a deficient number, since it is larger than the sum of its proper divisors (1055501006504).
2111002013002 is a wasteful number, since it uses less digits than its factorization.
2111002013002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1055501006503.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 2111002013002 its reverse (2003102001112), we get a palindrome (4114104014114).
The spelling of 2111002013002 in words is "two trillion, one hundred eleven billion, two million, thirteen thousand, two".
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