Base | Representation |
---|---|
bin | 11110101110000010000… |
… | …000001110100101010011 |
3 | 21110210212220211011221111 |
4 | 132232002000032211103 |
5 | 234041322032241042 |
6 | 4253441251234151 |
7 | 305341540164001 |
oct | 36560200164523 |
9 | 7423786734844 |
10 | 2111010040147 |
11 | 744302152018 |
12 | 2a1164ba8957 |
13 | 1240b50a5368 |
14 | 7425dc75a71 |
15 | 39da3adb517 |
hex | 1eb8200e953 |
2111010040147 has 2 divisors, whose sum is σ = 2111010040148. Its totient is φ = 2111010040146.
The previous prime is 2111010040141. The next prime is 2111010040157. The reversal of 2111010040147 is 7410400101112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111010040147 - 219 = 2111009515859 is a prime.
It is not a weakly prime, because it can be changed into another prime (2111010040141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055505020073 + 1055505020074.
It is an arithmetic number, because the mean of its divisors is an integer number (1055505020074).
Almost surely, 22111010040147 is an apocalyptic number.
2111010040147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111010040147 is an equidigital number, since it uses as much as digits as its factorization.
2111010040147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 2111010040147 its reverse (7410400101112), we get a palindrome (9521410141259).
The spelling of 2111010040147 in words is "two trillion, one hundred eleven billion, ten million, forty thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •