Base | Representation |
---|---|
bin | 101111111111111011011010… |
… | …101010111111000110100011 |
3 | 1000200110002101100101000120022 |
4 | 233333323122222333012203 |
5 | 210132140441143100003 |
6 | 2024550334213504055 |
7 | 62315365200402545 |
oct | 5777733252770643 |
9 | 1020402340330508 |
10 | 211101311300003 |
11 | 61299621913473 |
12 | 1b814a2204202b |
13 | 90a39caa85b17 |
14 | 3a1b50243d695 |
15 | 1961369b56738 |
hex | bffedaabf1a3 |
211101311300003 has 2 divisors, whose sum is σ = 211101311300004. Its totient is φ = 211101311300002.
The previous prime is 211101311299999. The next prime is 211101311300081. The reversal of 211101311300003 is 300003113101112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211101311300003 - 22 = 211101311299999 is a prime.
It is not a weakly prime, because it can be changed into another prime (211101311300203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105550655650001 + 105550655650002.
It is an arithmetic number, because the mean of its divisors is an integer number (105550655650002).
Almost surely, 2211101311300003 is an apocalyptic number.
211101311300003 is a deficient number, since it is larger than the sum of its proper divisors (1).
211101311300003 is an equidigital number, since it uses as much as digits as its factorization.
211101311300003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 211101311300003 its reverse (300003113101112), we get a palindrome (511104424401115).
The spelling of 211101311300003 in words is "two hundred eleven trillion, one hundred one billion, three hundred eleven million, three hundred thousand, three".
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