Base | Representation |
---|---|
bin | 101111111111111100001010… |
… | …111100100011100011011001 |
3 | 1000200110011110210100211010102 |
4 | 233333330022330203203121 |
5 | 210132144121012241441 |
6 | 2024550550425025145 |
7 | 62315424233501426 |
oct | 5777741274434331 |
9 | 1020404423324112 |
10 | 211102121212121 |
11 | 612999a8004427 |
12 | 1b8150093251b5 |
13 | 90a3ac97c9569 |
14 | 3a1b57bc28d4d |
15 | 19613b5cda69b |
hex | bfff0af238d9 |
211102121212121 has 4 divisors (see below), whose sum is σ = 211102712923044. Its totient is φ = 211101529501200.
The previous prime is 211102121212049. The next prime is 211102121212123. The reversal of 211102121212121 is 121212121201112.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 63416312926096 + 147685808286025 = 7963436^2 + 12152605^2 .
It is a cyclic number.
It is not a de Polignac number, because 211102121212121 - 238 = 210827243305177 is a prime.
It is a super-3 number, since 3×2111021212121213 (a number of 44 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 211102121212093 and 211102121212102.
It is not an unprimeable number, because it can be changed into a prime (211102121212123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 295319990 + ... + 296033951.
It is an arithmetic number, because the mean of its divisors is an integer number (52775678230761).
Almost surely, 2211102121212121 is an apocalyptic number.
It is an amenable number.
211102121212121 is a deficient number, since it is larger than the sum of its proper divisors (591710923).
211102121212121 is an equidigital number, since it uses as much as digits as its factorization.
211102121212121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 591710922.
The product of its (nonzero) digits is 64, while the sum is 20.
Adding to 211102121212121 its reverse (121212121201112), we get a palindrome (332314242413233).
The spelling of 211102121212121 in words is "two hundred eleven trillion, one hundred two billion, one hundred twenty-one million, two hundred twelve thousand, one hundred twenty-one".
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