Base | Representation |
---|---|
bin | 1100010010011010111… |
… | …0100010000110010000 |
3 | 202011220010210010111110 |
4 | 3010212232202012100 |
5 | 11424314400130000 |
6 | 240551320413320 |
7 | 21152221666260 |
oct | 3044656420620 |
9 | 664803703443 |
10 | 211103130000 |
11 | 8158a2390a4 |
12 | 34ab6017240 |
13 | 16ba3714b99 |
14 | a3089597a0 |
15 | 57580d5850 |
hex | 3126ba2190 |
211103130000 has 800 divisors, whose sum is σ = 810793463040. Its totient is φ = 46310400000.
The previous prime is 211103129999. The next prime is 211103130013. The reversal of 211103130000 is 31301112.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 784769866 + ... + 784770134.
Almost surely, 2211103130000 is an apocalyptic number.
211103130000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211103130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (405396731520).
211103130000 is an abundant number, since it is smaller than the sum of its proper divisors (599690333040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211103130000 is a wasteful number, since it uses less digits than its factorization.
211103130000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 445 (or 424 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 211103130000 its reverse (31301112), we get a palindrome (211134431112).
The spelling of 211103130000 in words is "two hundred eleven billion, one hundred three million, one hundred thirty thousand".
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