211110011113 has 2 divisors, whose sum is σ = 211110011114. Its totient is φ = 211110011112.

The previous prime is 211110011107. The next prime is 211110011117. The reversal of 211110011113 is 311110011112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151345897024 + 59764114089 = 389032^2 + 244467^2 .

It is a cyclic number.

It is not a de Polignac number, because 211110011113 - 2⁵ = 211110011081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211110011093 and 211110011102.

It is not a weakly prime, because it can be changed into another prime (211110011117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105555005556 + 105555005557.

It is an arithmetic number, because the mean of its divisors is an integer number (105555005557).

Almost surely, 2^211110011113 is an apocalyptic number.

It is an amenable number.

211110011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211110011113 is an equidigital number, since it uses as much as digits as its factorization.

211110011113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 211110011113 its reverse (311110011112), we get a palindrome (522220022225).

Subtracting 211110011113 from its reverse (311110011112), we obtain a palindrome (99999999999).

The spelling of 211110011113 in words is "two hundred eleven billion, one hundred ten million, eleven thousand, one hundred thirteen".