Base | Representation |
---|---|
bin | 11110101110001000001… |
… | …001011010111011010101 |
3 | 21110211011002202211201201 |
4 | 132232020021122323111 |
5 | 234042024424111201 |
6 | 4253455412352501 |
7 | 305344231245553 |
oct | 36561011327325 |
9 | 7424132684651 |
10 | 2111113113301 |
11 | 744355352445 |
12 | 2a1193615731 |
13 | 1241005538aa |
14 | 7426d826bd3 |
15 | 39dacb9b801 |
hex | 1eb8825aed5 |
2111113113301 has 4 divisors (see below), whose sum is σ = 2156030413632. Its totient is φ = 2066195812972.
The previous prime is 2111113113293. The next prime is 2111113113313. The reversal of 2111113113301 is 1033113111112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2111113113301 - 23 = 2111113113293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2111113113331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22458650095 + ... + 22458650188.
It is an arithmetic number, because the mean of its divisors is an integer number (539007603408).
Almost surely, 22111113113301 is an apocalyptic number.
It is an amenable number.
2111113113301 is a deficient number, since it is larger than the sum of its proper divisors (44917300331).
2111113113301 is an equidigital number, since it uses as much as digits as its factorization.
2111113113301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44917300330.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 2111113113301 its reverse (1033113111112), we get a palindrome (3144226224413).
The spelling of 2111113113301 in words is "two trillion, one hundred eleven billion, one hundred thirteen million, one hundred thirteen thousand, three hundred one".
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