Base | Representation |
---|---|
bin | 11110101110001000100… |
… | …111100000011100011001 |
3 | 21110211011122121112112201 |
4 | 132232020213200130121 |
5 | 234042033434001332 |
6 | 4253500253410201 |
7 | 305344355264515 |
oct | 36561047403431 |
9 | 7424148545481 |
10 | 2111121000217 |
11 | 744359849a59 |
12 | 2a1196199961 |
13 | 1241020856c8 |
14 | 742708bb145 |
15 | 39dad7085e7 |
hex | 1eb889e0719 |
2111121000217 has 2 divisors, whose sum is σ = 2111121000218. Its totient is φ = 2111121000216.
The previous prime is 2111121000203. The next prime is 2111121000251. The reversal of 2111121000217 is 7120001211112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1562952532761 + 548168467456 = 1250181^2 + 740384^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111121000217 - 219 = 2111120475929 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2111121000194 and 2111121000203.
It is not a weakly prime, because it can be changed into another prime (2111121000517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055560500108 + 1055560500109.
It is an arithmetic number, because the mean of its divisors is an integer number (1055560500109).
Almost surely, 22111121000217 is an apocalyptic number.
It is an amenable number.
2111121000217 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111121000217 is an equidigital number, since it uses as much as digits as its factorization.
2111121000217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 19.
Adding to 2111121000217 its reverse (7120001211112), we get a palindrome (9231122211329).
The spelling of 2111121000217 in words is "two trillion, one hundred eleven billion, one hundred twenty-one million, two hundred seventeen", and thus it is an aban number.
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