Base | Representation |
---|---|
bin | 1001100110011010101100… |
… | …01111101001011001010011 |
3 | 2202202012201121101100111001 |
4 | 10303031112033221121103 |
5 | 10231341230031432011 |
6 | 112522205002402431 |
7 | 4306143331263631 |
oct | 463152617513123 |
9 | 82665647340431 |
10 | 21111211202131 |
11 | 67aa23a3a0136 |
12 | 244b5b1b00417 |
13 | ba1a1799370b |
14 | 52db06692351 |
15 | 26923ebe47c1 |
hex | 1333563e9653 |
21111211202131 has 2 divisors, whose sum is σ = 21111211202132. Its totient is φ = 21111211202130.
The previous prime is 21111211202119. The next prime is 21111211202141. The reversal of 21111211202131 is 13120211211112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21111211202131 is a prime.
It is a super-2 number, since 2×211112112021312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21111211202099 and 21111211202108.
It is not a weakly prime, because it can be changed into another prime (21111211202141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10555605601065 + 10555605601066.
It is an arithmetic number, because the mean of its divisors is an integer number (10555605601066).
Almost surely, 221111211202131 is an apocalyptic number.
21111211202131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21111211202131 is an equidigital number, since it uses as much as digits as its factorization.
21111211202131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 21111211202131 its reverse (13120211211112), we get a palindrome (34231422413243).
The spelling of 21111211202131 in words is "twenty-one trillion, one hundred eleven billion, two hundred eleven million, two hundred two thousand, one hundred thirty-one".
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