Base | Representation |
---|---|
bin | 11110101110001000101… |
… | …011101111111001010001 |
3 | 21110211011201201000201212 |
4 | 132232020223233321101 |
5 | 234042034230041311 |
6 | 4253500333305505 |
7 | 305344400605223 |
oct | 36561053577121 |
9 | 7424151630655 |
10 | 2111122112081 |
11 | 74435a439354 |
12 | 2a1196635295 |
13 | 124102384808 |
14 | 74270aca413 |
15 | 39dad877c8b |
hex | 1eb88aefe51 |
2111122112081 has 2 divisors, whose sum is σ = 2111122112082. Its totient is φ = 2111122112080.
The previous prime is 2111122111909. The next prime is 2111122112087. The reversal of 2111122112081 is 1802112211112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1205549100625 + 905573011456 = 1097975^2 + 951616^2 .
It is a cyclic number.
It is not a de Polignac number, because 2111122112081 - 230 = 2110048370257 is a prime.
It is a super-2 number, since 2×21111221120812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111122112087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055561056040 + 1055561056041.
It is an arithmetic number, because the mean of its divisors is an integer number (1055561056041).
Almost surely, 22111122112081 is an apocalyptic number.
It is an amenable number.
2111122112081 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111122112081 is an equidigital number, since it uses as much as digits as its factorization.
2111122112081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 23.
Adding to 2111122112081 its reverse (1802112211112), we get a palindrome (3913234323193).
The spelling of 2111122112081 in words is "two trillion, one hundred eleven billion, one hundred twenty-two million, one hundred twelve thousand, eighty-one".
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