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211114153 is a prime number
BaseRepresentation
bin11001001010101…
…01100010101001
3112201020201011201
430211111202221
5413021123103
632540524201
75142304105
oct1445254251
9481221151
10211114153
11a9194208
125a850661
1334979023
1420076905
151380251d
hexc9558a9

211114153 has 2 divisors, whose sum is σ = 211114154. Its totient is φ = 211114152.

The previous prime is 211114129. The next prime is 211114201. The reversal of 211114153 is 351411112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 205291584 + 5822569 = 14328^2 + 2413^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211114153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 211114153.

It is not a weakly prime, because it can be changed into another prime (217114153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105557076 + 105557077.

It is an arithmetic number, because the mean of its divisors is an integer number (105557077).

Almost surely, 2211114153 is an apocalyptic number.

It is an amenable number.

211114153 is a deficient number, since it is larger than the sum of its proper divisors (1).

211114153 is an equidigital number, since it uses as much as digits as its factorization.

211114153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 19.

The square root of 211114153 is about 14529.7678233343. The cubic root of 211114153 is about 595.4415224371.

Adding to 211114153 its reverse (351411112), we get a palindrome (562525265).

The spelling of 211114153 in words is "two hundred eleven million, one hundred fourteen thousand, one hundred fifty-three".