Base | Representation |
---|---|
bin | 11110101110001110000… |
… | …010101001011111100011 |
3 | 21110211101222211212111101 |
4 | 132232032002221133203 |
5 | 234042230233020001 |
6 | 4253513304055231 |
7 | 305346541626613 |
oct | 36561602513743 |
9 | 7424358755441 |
10 | 2111212001251 |
11 | 7443a6154421 |
12 | 2a1200764517 |
13 | 124117b98182 |
14 | 7427ca08a43 |
15 | 39db66d1a01 |
hex | 1eb8e0a97e3 |
2111212001251 has 2 divisors, whose sum is σ = 2111212001252. Its totient is φ = 2111212001250.
The previous prime is 2111212001209. The next prime is 2111212001341. The reversal of 2111212001251 is 1521002121112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2111212001251 - 27 = 2111212001123 is a prime.
It is a super-2 number, since 2×21112120012512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2111212001051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055606000625 + 1055606000626.
It is an arithmetic number, because the mean of its divisors is an integer number (1055606000626).
Almost surely, 22111212001251 is an apocalyptic number.
2111212001251 is a deficient number, since it is larger than the sum of its proper divisors (1).
2111212001251 is an equidigital number, since it uses as much as digits as its factorization.
2111212001251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 2111212001251 its reverse (1521002121112), we get a palindrome (3632214122363).
The spelling of 2111212001251 in words is "two trillion, one hundred eleven billion, two hundred twelve million, one thousand, two hundred fifty-one".
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