Base | Representation |
---|---|
bin | 110000000000001110101101… |
… | …000101000011111101110011 |
3 | 1000200112001211122201222021002 |
4 | 300000032231011003331303 |
5 | 210133010344413021321 |
6 | 2025004041223152215 |
7 | 62320030332665633 |
oct | 6000165505037563 |
9 | 1020461748658232 |
10 | 211122021220211 |
11 | 612a738a048002 |
12 | 1b818a418a566b |
13 | 90a594b56428a |
14 | 3a1c508b226c3 |
15 | 1961b7cda420b |
hex | c003ad143f73 |
211122021220211 has 2 divisors, whose sum is σ = 211122021220212. Its totient is φ = 211122021220210.
The previous prime is 211122021220169. The next prime is 211122021220261. The reversal of 211122021220211 is 112022120221112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211122021220211 is a prime.
It is not a weakly prime, because it can be changed into another prime (211122021220261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105561010610105 + 105561010610106.
It is an arithmetic number, because the mean of its divisors is an integer number (105561010610106).
Almost surely, 2211122021220211 is an apocalyptic number.
211122021220211 is a deficient number, since it is larger than the sum of its proper divisors (1).
211122021220211 is an equidigital number, since it uses as much as digits as its factorization.
211122021220211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 20.
Adding to 211122021220211 its reverse (112022120221112), we get a palindrome (323144141441323).
Subtracting from 211122021220211 its reverse (112022120221112), we obtain a palindrome (99099900999099).
The spelling of 211122021220211 in words is "two hundred eleven trillion, one hundred twenty-two billion, twenty-one million, two hundred twenty thousand, two hundred eleven".
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