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211125343151 = 1049472011733
BaseRepresentation
bin1100010010100000001…
…1010001001110101111
3202011221200120200012202
43010220003101032233
511424341041440101
6240553432452115
721152611543532
oct3045003211657
9664850520182
10211125343151
11815a0830178
1234b0154a03b
1316ba81c1768
14a30b89ca19
15575a02236b
hex31280d13af

211125343151 has 4 divisors (see below), whose sum is σ = 211127459832. Its totient is φ = 211123226472.

The previous prime is 211125343141. The next prime is 211125343183. The reversal of 211125343151 is 151343521112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211125343151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211125343141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 900920 + ... + 1110813.

It is an arithmetic number, because the mean of its divisors is an integer number (52781864958).

Almost surely, 2211125343151 is an apocalyptic number.

211125343151 is a deficient number, since it is larger than the sum of its proper divisors (2116681).

211125343151 is a wasteful number, since it uses less digits than its factorization.

211125343151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2116680.

The product of its digits is 3600, while the sum is 29.

Adding to 211125343151 its reverse (151343521112), we get a palindrome (362468864263).

The spelling of 211125343151 in words is "two hundred eleven billion, one hundred twenty-five million, three hundred forty-three thousand, one hundred fifty-one".

Divisors: 1 104947 2011733 211125343151